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156 lines
6.1 KiB
Plaintext
156 lines
6.1 KiB
Plaintext
/* Copyright (c) 2020, NVIDIA CORPORATION. All rights reserved.
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*
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* Redistribution and use in source and binary forms, with or without
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* modification, are permitted provided that the following conditions
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* are met:
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* * Redistributions of source code must retain the above copyright
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* notice, this list of conditions and the following disclaimer.
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* * Redistributions in binary form must reproduce the above copyright
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* notice, this list of conditions and the following disclaimer in the
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* documentation and/or other materials provided with the distribution.
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* * Neither the name of NVIDIA CORPORATION nor the names of its
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* contributors may be used to endorse or promote products derived
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* from this software without specific prior written permission.
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*
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* THIS SOFTWARE IS PROVIDED BY THE COPYRIGHT HOLDERS ``AS IS'' AND ANY
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* EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE
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* IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR
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* PURPOSE ARE DISCLAIMED. IN NO EVENT SHALL THE COPYRIGHT OWNER OR
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* CONTRIBUTORS BE LIABLE FOR ANY DIRECT, INDIRECT, INCIDENTAL, SPECIAL,
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* EXEMPLARY, OR CONSEQUENTIAL DAMAGES (INCLUDING, BUT NOT LIMITED TO,
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* PROCUREMENT OF SUBSTITUTE GOODS OR SERVICES; LOSS OF USE, DATA, OR
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* PROFITS; OR BUSINESS INTERRUPTION) HOWEVER CAUSED AND ON ANY THEORY
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* OF LIABILITY, WHETHER IN CONTRACT, STRICT LIABILITY, OR TORT
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* (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY OUT OF THE USE
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* OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF SUCH DAMAGE.
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*/
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/*
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* This sample illustrates basic usage of binary partition cooperative groups
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* within the thread block tile when divergent path exists.
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* 1.) Each thread loads a value from random array.
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* 2.) then checks if it is odd or even.
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* 3.) create binary partition group based on the above predicate
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* 4.) we count the number of odd/even in the group based on size of the binary groups
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* 5.) write it global counter of odd.
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* 6.) sum the values loaded by individual threads(using reduce) and write it to global
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* even & odd elements sum.
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*
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* **NOTE** : binary_partition results in splitting warp into divergent thread groups
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this is not good from performance perspective, but in cases where warp
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divergence is inevitable one can use binary_partition group.
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*/
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#include <stdio.h>
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#include <cooperative_groups.h>
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#include <cooperative_groups/reduce.h>
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#include <helper_cuda.h>
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namespace cg = cooperative_groups;
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void initOddEvenArr(int *inputArr, unsigned int size)
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{
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for (int i=0; i < size; i++)
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{
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inputArr[i] = rand() % 50;
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}
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}
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/**
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* CUDA kernel device code
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*
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* Creates cooperative groups and performs odd/even counting & summation.
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*/
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__global__ void oddEvenCountAndSumCG(int *inputArr, int *numOfOdds, int *sumOfOddAndEvens, unsigned int size)
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{
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cg::thread_block cta = cg::this_thread_block();
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cg::grid_group grid = cg::this_grid();
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cg::thread_block_tile<32> tile32 = cg::tiled_partition<32>(cta);
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for (int i = grid.thread_rank(); i < size; i += grid.size())
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{
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int elem = inputArr[i];
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auto subTile = cg::binary_partition(tile32, elem & 1);
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if (elem & 1) // Odd numbers group
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{
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int oddGroupSum = cg::reduce(subTile, elem, cg::plus<int>());
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if (subTile.thread_rank() == 0)
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{
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// Add number of odds present in this group of Odds.
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atomicAdd(numOfOdds, subTile.size());
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// Add local reduction of odds present in this group of Odds.
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atomicAdd(&sumOfOddAndEvens[0], oddGroupSum);
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}
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}
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else // Even numbers group
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{
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int evenGroupSum = cg::reduce(subTile, elem, cg::plus<int>());
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if (subTile.thread_rank() == 0)
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{
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// Add local reduction of even present in this group of evens.
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atomicAdd(&sumOfOddAndEvens[1], evenGroupSum);
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}
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}
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// reconverge warp so for next loop iteration we ensure convergence of
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// above diverged threads to perform coalesced loads of inputArr.
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cg::sync(tile32);
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}
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}
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/**
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* Host main routine
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*/
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int main(int argc, const char **argv)
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{
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int deviceId = findCudaDevice(argc, argv);
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int *h_inputArr, *d_inputArr;
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int *h_numOfOdds, *d_numOfOdds;
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int *h_sumOfOddEvenElems, *d_sumOfOddEvenElems;
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unsigned int arrSize = 1024 * 100;
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h_inputArr = new int[arrSize];
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h_numOfOdds = new int[1];
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h_sumOfOddEvenElems = new int[2];
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initOddEvenArr(h_inputArr, arrSize);
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cudaStream_t stream;
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checkCudaErrors(cudaStreamCreateWithFlags(&stream, cudaStreamNonBlocking));
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checkCudaErrors(cudaMalloc(&d_inputArr, sizeof(int)*arrSize));
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checkCudaErrors(cudaMalloc(&d_numOfOdds, sizeof(int)));
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checkCudaErrors(cudaMalloc(&d_sumOfOddEvenElems, sizeof(int)*2));
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checkCudaErrors(cudaMemcpyAsync(d_inputArr, h_inputArr, sizeof(int)*arrSize, cudaMemcpyHostToDevice, stream));
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checkCudaErrors(cudaMemsetAsync(d_numOfOdds, 0, sizeof(int), stream));
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checkCudaErrors(cudaMemsetAsync(d_sumOfOddEvenElems, 0, 2*sizeof(int), stream));
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//Launch the kernel
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int threadsPerBlock=1024;
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int blocksPerGrid = arrSize / threadsPerBlock;
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printf("\nLaunching %d blocks with %d threads...\n\n",blocksPerGrid, threadsPerBlock);
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oddEvenCountAndSumCG<<<blocksPerGrid, threadsPerBlock, 0, stream>>>(d_inputArr, d_numOfOdds, d_sumOfOddEvenElems, arrSize);
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checkCudaErrors(cudaMemcpyAsync(h_numOfOdds, d_numOfOdds, sizeof(int), cudaMemcpyDeviceToHost, stream));
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checkCudaErrors(cudaMemcpyAsync(h_sumOfOddEvenElems, d_sumOfOddEvenElems, 2*sizeof(int), cudaMemcpyDeviceToHost, stream));
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printf("Array size = %d Num of Odds = %d Sum of Odds = %d Sum of Evens %d\n", arrSize, h_numOfOdds[0], h_sumOfOddEvenElems[0], h_sumOfOddEvenElems[1]);
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printf("\n...Done.\n\n");
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delete[] h_inputArr;
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delete[] h_numOfOdds;
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delete[] h_sumOfOddEvenElems;
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checkCudaErrors(cudaFree(d_inputArr));
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checkCudaErrors(cudaFree(d_numOfOdds));
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checkCudaErrors(cudaFree(d_sumOfOddEvenElems));
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return EXIT_SUCCESS;
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}
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