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360 lines
11 KiB
Plaintext
360 lines
11 KiB
Plaintext
/* Copyright (c) 2019, NVIDIA CORPORATION. All rights reserved.
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*
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* Redistribution and use in source and binary forms, with or without
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* modification, are permitted provided that the following conditions
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* are met:
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* * Redistributions of source code must retain the above copyright
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* notice, this list of conditions and the following disclaimer.
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* * Redistributions in binary form must reproduce the above copyright
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* notice, this list of conditions and the following disclaimer in the
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* documentation and/or other materials provided with the distribution.
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* * Neither the name of NVIDIA CORPORATION nor the names of its
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* contributors may be used to endorse or promote products derived
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* from this software without specific prior written permission.
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*
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* THIS SOFTWARE IS PROVIDED BY THE COPYRIGHT HOLDERS ``AS IS'' AND ANY
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* EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE
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* IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR
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* PURPOSE ARE DISCLAIMED. IN NO EVENT SHALL THE COPYRIGHT OWNER OR
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* CONTRIBUTORS BE LIABLE FOR ANY DIRECT, INDIRECT, INCIDENTAL, SPECIAL,
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* EXEMPLARY, OR CONSEQUENTIAL DAMAGES (INCLUDING, BUT NOT LIMITED TO,
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* PROCUREMENT OF SUBSTITUTE GOODS OR SERVICES; LOSS OF USE, DATA, OR
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* PROFITS; OR BUSINESS INTERRUPTION) HOWEVER CAUSED AND ON ANY THEORY
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* OF LIABILITY, WHETHER IN CONTRACT, STRICT LIABILITY, OR TORT
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* (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY OUT OF THE USE
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* OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF SUCH DAMAGE.
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*/
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// Utility function to extract unsigned chars from an
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// unsigned integer
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__device__ uchar4 int_to_uchar4(unsigned int in) {
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uchar4 bytes;
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bytes.x = in & 0x000000ff >> 0;
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bytes.y = in & 0x0000ff00 >> 8;
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bytes.z = in & 0x00ff0000 >> 16;
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bytes.w = in & 0xff000000 >> 24;
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return bytes;
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}
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// This function demonstrates some uses of the shuffle instruction
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// in the generation of an integral image (also
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// called a summed area table)
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// The approach is two pass, a horizontal (scanline) then a vertical
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// (column) pass.
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// This is the horizontal pass kernel.
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__global__ void shfl_intimage_rows(uint4 *img, uint4 *integral_image) {
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__shared__ int sums[128];
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int id = threadIdx.x;
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// pointer to head of current scanline
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uint4 *scanline = &img[blockIdx.x * 120];
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uint4 data;
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data = scanline[id];
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int result[16];
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int sum;
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unsigned int lane_id = id % warpSize;
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int warp_id = threadIdx.x / warpSize;
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uchar4 a = int_to_uchar4(data.x);
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uchar4 b = int_to_uchar4(data.y);
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uchar4 c = int_to_uchar4(data.z);
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uchar4 d = int_to_uchar4(data.w);
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result[0] = a.x;
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result[1] = a.x + a.y;
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result[2] = a.x + a.y + a.z;
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result[3] = a.x + a.y + a.z + a.w;
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result[4] = b.x;
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result[5] = b.x + b.y;
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result[6] = b.x + b.y + b.z;
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result[7] = b.x + b.y + b.z + b.w;
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result[8] = c.x;
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result[9] = c.x + c.y;
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result[10] = c.x + c.y + c.z;
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result[11] = c.x + c.y + c.z + c.w;
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result[12] = d.x;
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result[13] = d.x + d.y;
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result[14] = d.x + d.y + d.z;
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result[15] = d.x + d.y + d.z + d.w;
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#pragma unroll
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for (int i = 4; i <= 7; i++) result[i] += result[3];
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#pragma unroll
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for (int i = 8; i <= 11; i++) result[i] += result[7];
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#pragma unroll
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for (int i = 12; i <= 15; i++) result[i] += result[11];
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sum = result[15];
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// the prefix sum for each thread's 16 value is computed,
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// now the final sums (result[15]) need to be shared
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// with the other threads and add. To do this,
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// the __shfl_up() instruction is used and a shuffle scan
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// operation is performed to distribute the sums to the correct
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// threads
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#pragma unroll
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for (int i = 1; i < 32; i *= 2) {
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unsigned int mask = 0xffffffff;
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int n = __shfl_up_sync(mask, sum, i, 32);
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if (lane_id >= i) {
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#pragma unroll
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for (int i = 0; i < 16; i++) {
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result[i] += n;
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}
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sum += n;
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}
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}
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// Now the final sum for the warp must be shared
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// between warps. This is done by each warp
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// having a thread store to shared memory, then
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// having some other warp load the values and
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// compute a prefix sum, again by using __shfl_up.
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// The results are uniformly added back to the warps.
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// last thread in the warp holding sum of the warp
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// places that in shared
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if (threadIdx.x % warpSize == warpSize - 1) {
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sums[warp_id] = result[15];
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}
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__syncthreads();
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if (warp_id == 0) {
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int warp_sum = sums[lane_id];
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#pragma unroll
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for (int i = 1; i <= 32; i *= 2) {
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unsigned int mask = 0xffffffff;
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int n = __shfl_up_sync(mask, warp_sum, i, 32);
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if (lane_id >= i) warp_sum += n;
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}
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sums[lane_id] = warp_sum;
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}
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__syncthreads();
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int blockSum = 0;
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// fold in unused warp
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if (warp_id > 0) {
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blockSum = sums[warp_id - 1];
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#pragma unroll
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for (int i = 0; i < 16; i++) {
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result[i] += blockSum;
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}
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}
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// assemble result
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// Each thread has 16 values to write, which are
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// now integer data (to avoid overflow). Instead of
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// each thread writing consecutive uint4s, the
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// approach shown here experiments using
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// the shuffle command to reformat the data
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// inside the registers so that each thread holds
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// consecutive data to be written so larger contiguous
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// segments can be assembled for writing.
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/*
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For example data that needs to be written as
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GMEM[16] <- x0 x1 x2 x3 y0 y1 y2 y3 z0 z1 z2 z3 w0 w1 w2 w3
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but is stored in registers (r0..r3), in four threads (0..3) as:
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threadId 0 1 2 3
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r0 x0 y0 z0 w0
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r1 x1 y1 z1 w1
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r2 x2 y2 z2 w2
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r3 x3 y3 z3 w3
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after apply __shfl_xor operations to move data between registers r1..r3:
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threadId 00 01 10 11
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x0 y0 z0 w0
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xor(01)->y1 x1 w1 z1
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xor(10)->z2 w2 x2 y2
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xor(11)->w3 z3 y3 x3
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and now x0..x3, and z0..z3 can be written out in order by all threads.
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In the current code, each register above is actually representing
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four integers to be written as uint4's to GMEM.
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*/
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unsigned int mask = 0xffffffff;
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uint4 output;
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result[4] = __shfl_xor_sync(mask, result[4], 1, 32);
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result[5] = __shfl_xor_sync(mask, result[5], 1, 32);
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result[6] = __shfl_xor_sync(mask, result[6], 1, 32);
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result[7] = __shfl_xor_sync(mask, result[7], 1, 32);
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result[8] = __shfl_xor_sync(mask, result[8], 2, 32);
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result[9] = __shfl_xor_sync(mask, result[9], 2, 32);
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result[10] = __shfl_xor_sync(mask, result[10], 2, 32);
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result[11] = __shfl_xor_sync(mask, result[11], 2, 32);
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result[12] = __shfl_xor_sync(mask, result[12], 3, 32);
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result[13] = __shfl_xor_sync(mask, result[13], 3, 32);
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result[14] = __shfl_xor_sync(mask, result[14], 3, 32);
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result[15] = __shfl_xor_sync(mask, result[15], 3, 32);
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if (threadIdx.x % 4 == 0) {
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output = make_uint4(result[0], result[1], result[2], result[3]);
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}
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if (threadIdx.x % 4 == 1) {
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output = make_uint4(result[4], result[5], result[6], result[7]);
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}
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if (threadIdx.x % 4 == 2) {
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output = make_uint4(result[8], result[9], result[10], result[11]);
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}
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if (threadIdx.x % 4 == 3) {
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output = make_uint4(result[12], result[13], result[14], result[15]);
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}
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integral_image[blockIdx.x * 480 + threadIdx.x % 4 + (threadIdx.x / 4) * 16] =
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output;
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if (threadIdx.x % 4 == 2) {
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output = make_uint4(result[0], result[1], result[2], result[3]);
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}
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if (threadIdx.x % 4 == 3) {
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output = make_uint4(result[4], result[5], result[6], result[7]);
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}
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if (threadIdx.x % 4 == 0) {
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output = make_uint4(result[8], result[9], result[10], result[11]);
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}
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if (threadIdx.x % 4 == 1) {
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output = make_uint4(result[12], result[13], result[14], result[15]);
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}
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integral_image[blockIdx.x * 480 + (threadIdx.x + 2) % 4 +
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(threadIdx.x / 4) * 16 + 8] = output;
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// continuing from the above example,
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// this use of __shfl_xor() places the y0..y3 and w0..w3 data
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// in order.
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#pragma unroll
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for (int i = 0; i < 16; i++) {
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result[i] = __shfl_xor_sync(mask, result[i], 1, 32);
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}
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if (threadIdx.x % 4 == 0) {
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output = make_uint4(result[0], result[1], result[2], result[3]);
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}
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if (threadIdx.x % 4 == 1) {
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output = make_uint4(result[4], result[5], result[6], result[7]);
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}
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if (threadIdx.x % 4 == 2) {
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output = make_uint4(result[8], result[9], result[10], result[11]);
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}
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if (threadIdx.x % 4 == 3) {
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output = make_uint4(result[12], result[13], result[14], result[15]);
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}
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integral_image[blockIdx.x * 480 + threadIdx.x % 4 + (threadIdx.x / 4) * 16 +
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4] = output;
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if (threadIdx.x % 4 == 2) {
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output = make_uint4(result[0], result[1], result[2], result[3]);
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}
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if (threadIdx.x % 4 == 3) {
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output = make_uint4(result[4], result[5], result[6], result[7]);
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}
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if (threadIdx.x % 4 == 0) {
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output = make_uint4(result[8], result[9], result[10], result[11]);
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}
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if (threadIdx.x % 4 == 1) {
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output = make_uint4(result[12], result[13], result[14], result[15]);
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}
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integral_image[blockIdx.x * 480 + (threadIdx.x + 2) % 4 +
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(threadIdx.x / 4) * 16 + 12] = output;
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}
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// This kernel computes columnwise prefix sums. When the data input is
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// the row sums from above, this completes the integral image.
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// The approach here is to have each block compute a local set of sums.
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// First , the data covered by the block is loaded into shared memory,
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// then instead of performing a sum in shared memory using __syncthreads
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// between stages, the data is reformatted so that the necessary sums
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// occur inside warps and the shuffle scan operation is used.
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// The final set of sums from the block is then propagated, with the block
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// computing "down" the image and adding the running sum to the local
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// block sums.
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__global__ void shfl_vertical_shfl(unsigned int *img, int width, int height) {
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__shared__ unsigned int sums[32][9];
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int tidx = blockIdx.x * blockDim.x + threadIdx.x;
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// int warp_id = threadIdx.x / warpSize ;
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unsigned int lane_id = tidx % 8;
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// int rows_per_thread = (height / blockDim. y) ;
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// int start_row = rows_per_thread * threadIdx.y;
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unsigned int stepSum = 0;
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unsigned int mask = 0xffffffff;
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sums[threadIdx.x][threadIdx.y] = 0;
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__syncthreads();
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for (int step = 0; step < 135; step++) {
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unsigned int sum = 0;
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unsigned int *p = img + (threadIdx.y + step * 8) * width + tidx;
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sum = *p;
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sums[threadIdx.x][threadIdx.y] = sum;
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__syncthreads();
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// place into SMEM
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// shfl scan reduce the SMEM, reformating so the column
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// sums are computed in a warp
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// then read out properly
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int partial_sum = 0;
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int j = threadIdx.x % 8;
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int k = threadIdx.x / 8 + threadIdx.y * 4;
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partial_sum = sums[k][j];
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for (int i = 1; i <= 8; i *= 2) {
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int n = __shfl_up_sync(mask, partial_sum, i, 32);
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if (lane_id >= i) partial_sum += n;
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}
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sums[k][j] = partial_sum;
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__syncthreads();
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if (threadIdx.y > 0) {
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sum += sums[threadIdx.x][threadIdx.y - 1];
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}
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sum += stepSum;
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stepSum += sums[threadIdx.x][blockDim.y - 1];
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__syncthreads();
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*p = sum;
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}
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}
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